What is the force between two small charged spheres having charges of 2 × 10–7C and 3 × 10–7 C placed 30 cm apart in the air?

The force between two small charged spheres having charges of 2 × 10-7C and 3 × 10-7 C placed 30 cm apart in the air is 6 × 10-3 N.

The force between two charged particles is given by the following equation:

``` F = k * q1 * q2 / r2 ```

where:

  • F is the force between the particles (in Newtons)
  • k is the Coulomb constant (8.987551787 × 109)
  • q1 and q2 are the charges of the particles (in Coulombs)
  • r is the distance between the particles (in meters)

In this case, we have:

  • q1 = 2 × 10-7 C
  • q2 = 3 × 10-7 C
  • r = 0.3 m = 30 cm

Plugging these values into the equation, we get:

``` F = (8.987551787 × 109) * (2 × 10-7) * (3 × 10-7) / (0.3)^2 = 6 × 10-3 N ```

Therefore, the force between the two charged spheres is 6 × 10-3 N. This is a repulsive force, since the charges have the same sign.

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